A weak acid HX has the dissociation constant | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The salt $NaX$ is formed from a weak acid $HX$ and a strong base $NaOH$. The hydrolysis reaction is: $X^{-} + H_2O ⇌ HX + OH^{-}$.The hydrolysis c

Vedclass · Accepted Answer

$0.01$

Vedclass · Answer

(B) The salt $NaX$ is formed from a weak acid $HX$ and a strong base $NaOH$. The hydrolysis reaction is: $X^{-} + H_2O ⇌ HX + OH^{-}$.The hydrolysis constant $K_h$ is given by $K_h = \frac{K_w}{K_a} = \frac{10^{-14}}{10^{-5}} = 10^{-9}$.The degree of hydrolysis $h$ for a salt of a weak acid and strong base is given by $h = \sqrt{\frac{K_h}{C}}$,where $C = 0.1 \ M$.$h = \sqrt{\frac{10^{-9}}{0.1}} = \sqrt{10^{-8}} = 10^{-4}$.To express this as a percentage: $h 	imes 100 = 10^{-4} 	imes 100 = 0.01 \%$.

$A$ weak acid $HX$ has the dissociation constant $1 \times 10^{-5} \ M$. It forms a salt $NaX$ on reaction with alkali. The degree of hydrolysis of $0.1 \ M$ solution of $NaX$ is......$\%$

Similar Questions

Which of the following has the lowest degree of hydrolysis?

$A$ solution of $MgCl_2$ in water has $pH$:

Which of the following $0.1 \ M$ solutions of compounds will be basic in nature?

An aqueous solution of aluminium sulphate would show

The degree of hydrolysis of a salt of a weak acid and a weak base in its $0.1 \ M$ solution is found to be $50 \ \%$. If the molarity of the solution of the same salt is $0.5 \ M$,then the percentage degree of hydrolysis of the salt should be ......... $\%.$

Vedclass Test Series

Exam Paper Generator

Online Exam Module