(A) Initial angular velocity $\omega_0 = 720 \text{ rpm} = \frac{720}{60} \text{ rev/s} = 12 \text{ rev/s}$.Final angular velocity $\omega = 0 \text{

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(A) Initial angular velocity $\omega_0 = 720 \text{ rpm} = \frac{720}{60} \text{ rev/s} = 12 \text{ rev/s}$.Final angular velocity $\omega = 0 \text{ rev/s}$.Time taken $t = 8 \text{ s}$.Since the torque is constant,the angular acceleration is constant,and we can use the average angular velocity formula to find the total displacement (number of revolutions $\theta$):$\theta = \left( \frac{\omega + \omega_0}{2} \right) \times t$$\theta = \left( \frac{0 + 12}{2} \right) \times 8$$\theta = 6 \times 8 = 48 \text{ revolutions}$.

Class 11 Physics System of Particles and Rotational Motion Relation between Torque and Angular acceleration and it's Application

Medium

$A$ wheel is rotating about an axis through its centre at $720$ revolutions per minute. It is acted on by a constant torque opposing its motion for $8$ seconds until it comes to rest. The number of revolutions made by the wheel in the $8$ seconds is:

A
$48$
B
$72$
C
$96$
D
$120$

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Class 11 Questions

Class 11

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Chapter

System of Particles and Rotational Motion

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Relation between Torque and Angular acceleration and it's Application

In the given figure,$r_1$ and $r_2$ are $10 \ cm$ and $20 \ cm$ respectively. If the moment of inertia of the wheel is $1500 \ kg \cdot m^2$,find the angular acceleration.

Medium

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If a constant torque acts on an object,then the object:

Easy

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The angular velocity of a body changes from $6 \ rad \ s^{-1}$ to $21 \ rad \ s^{-1}$ in a time of $1.5 \ s$. If the moment of inertia of the body is $100 \ g \ m^2$,then the rate of change of angular momentum of the body is (in $N \ m$)

MediumAP EAMCET 2025

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$A$ disc of mass $10 \ kg$ and radius $0.1 \ m$ is rotating at $120 \ rpm$. $A$ retarding torque brings it to rest in $10 \ s$. If the same torque is due to a force applied tangentially on the rim of the disc, then the magnitude of the force is: (in $\pi \ N$)

MediumMHT CET 2020

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$A$ wheel is rotating at a rate of $900$ revolutions per minute about its axis. When the power source is cut off,it comes to rest in $1$ minute. The angular retardation of the wheel in $rad/s^2$ is:

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$A$ wheel is rotating about an axis through its centre at $720$ revolutions per minute. It is acted on by a constant torque opposing its motion for $8$ seconds until it comes to rest. The number of revolutions made by the wheel in the $8$ seconds is:

Similar Questions

In the given figure,$r_1$ and $r_2$ are $10 \ cm$ and $20 \ cm$ respectively. If the moment of inertia of the wheel is $1500 \ kg \cdot m^2$,find the angular acceleration.

If a constant torque acts on an object,then the object:

The angular velocity of a body changes from $6 \ rad \ s^{-1}$ to $21 \ rad \ s^{-1}$ in a time of $1.5 \ s$. If the moment of inertia of the body is $100 \ g \ m^2$,then the rate of change of angular momentum of the body is (in $N \ m$)

$A$ disc of mass $10 \ kg$ and radius $0.1 \ m$ is rotating at $120 \ rpm$. $A$ retarding torque brings it to rest in $10 \ s$. If the same torque is due to a force applied tangentially on the rim of the disc, then the magnitude of the force is: (in $\pi \ N$)

$A$ wheel is rotating at a rate of $900$ revolutions per minute about its axis. When the power source is cut off,it comes to rest in $1$ minute. The angular retardation of the wheel in $rad/s^2$ is:

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