(A) The elastic potential energy $(U)$ stored in a stretched wire is given by the formula:$U = \frac{1}{2} \times F \times x$Where:$F = 200 \,N$ (the

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(A) The elastic potential energy $(U)$ stored in a stretched wire is given by the formula:$U = \frac{1}{2} \times F \times x$Where:$F = 200 \,N$ (the applied force)$x = 1 \,mm = 1 \times 10^{-3} \,m$ (the elongation)Substituting the values into the formula:$U = \frac{1}{2} \times 200 \times (1 \times 10^{-3})$$U = 100 \times 0.001$$U = 0.1 \,J$Thus,the elastic potential energy gained by the wire is $0.1 \,J$.

Class 11 Physics Mechanical Properties of Solids Work Done in Stretching a Wire

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$A$ wire suspended vertically from one end is stretched by attaching a weight $200 \,N$ to the lower end. The weight stretches the wire by $1 \,mm$. The elastic potential energy gained by the wire is ....... $J$

A
$0.1$
B
$0.2$
C
$0.4$
D
$10$

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Mechanical Properties of Solids

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Work Done in Stretching a Wire

Determine the elastic potential energy stored in a stretched wire.

Medium

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$A$ wire of length $L$ and cross-sectional area $A$ is made of a material of Young's modulus $Y$. It is stretched by an amount $x$. The work done is

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$A$ wire $2 \,m$ in length suspended vertically stretches by $10 \,mm$ when a mass of $10 \,kg$ is attached to the lower end. The elastic potential energy gained by the wire is ...... $J$ (take $g=10 \,m/s^2$)

Easy

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Identical springs of steel and copper are equally stretched. On which more work will have to be done?

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The elastic potential energy stored in a copper rod of length $1 \,m$ and area of cross-section $1 \,mm^2$ when stretched by $1 \,mm$ is (Young's modulus of copper $= 1.2 \times 10^{11} \,N/m^2$).

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$A$ wire suspended vertically from one end is stretched by attaching a weight $200 \,N$ to the lower end. The weight stretches the wire by $1 \,mm$. The elastic potential energy gained by the wire is ....... $J$

Similar Questions

Determine the elastic potential energy stored in a stretched wire.

$A$ wire of length $L$ and cross-sectional area $A$ is made of a material of Young's modulus $Y$. It is stretched by an amount $x$. The work done is

$A$ wire $2 \,m$ in length suspended vertically stretches by $10 \,mm$ when a mass of $10 \,kg$ is attached to the lower end. The elastic potential energy gained by the wire is ...... $J$ (take $g=10 \,m/s^2$)

Identical springs of steel and copper are equally stretched. On which more work will have to be done?

The elastic potential energy stored in a copper rod of length $1 \,m$ and area of cross-section $1 \,mm^2$ when stretched by $1 \,mm$ is (Young's modulus of copper $= 1.2 \times 10^{11} \,N/m^2$).

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