A woman carrying two genes for haemophilia an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the $X$ chromosome carrying the genes for haemophilia and colour blindness be denoted as $X^{hc}$. The normal $X$ chromosome is $X$. The woman

Vedclass · Accepted Answer

$50\%$ haemophilic colourblind sons and $50\%$ normal sons

Vedclass · Answer

(C) Let the $X$ chromosome carrying the genes for haemophilia and colour blindness be denoted as $X^{hc}$. The normal $X$ chromosome is $X$. The woman's genotype is $X^{hc}X$. The normal man's genotype is $XY$.Cross: $X^{hc}X 	imes XY$Gametes: $(X^{hc}, X)$ and $(X, Y)$Progeny genotypes: $X^{hc}X$ (carrier daughter),$X^{hc}Y$ (haemophilic and colourblind son),$XX$ (normal daughter),$XY$ (normal son).Thus,$50\%$ of the sons will be haemophilic and colourblind,and $50\%$ of the sons will be normal.

$A$ woman carrying two genes for haemophilia and one gene for colour blindness on one of her $X$ chromosomes marries a normal man. What will be the phenotype of the progeny?

Similar Questions

If a colourblind woman marries a normal man whose father was colourblind,what are the chances of their son being colourblind (in $\%$)?

In humans,color blindness is caused by:

The blackening of urine when exposed to air is a metabolic disorder in human beings. This is due to the presence of:

If a colour-blind man marries a woman who is homozygous for normal colour vision,the probability of their son being colour-blind is

$A$ colour-blind son will be born when:

Vedclass Test Series

Exam Paper Generator

Online Exam Module