(B) The number of half-lives $(n)$ is calculated as: $n = \frac{\text{Total time}}{\text{Half-life}} = \frac{11460}{5730} = 2$. The fraction of activi

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(B) The number of half-lives $(n)$ is calculated as: $n = \frac{\text{Total time}}{\text{Half-life}} = \frac{11460}{5730} = 2$. The fraction of activity remaining is given by the formula: $\text{Fraction} = (\frac{1}{2})^n$. Substituting $n = 2$,we get: $\text{Fraction} = (\frac{1}{2})^2 = \frac{1}{4} = 0.25$. Therefore,the correct option is $B$.

Class 12 Chemistry Nuclear Chemistry Rate of decay and Half-life

Medium

$A$ wood piece is $11460$ years old. What is the fraction of $^{14}C$ activity left in the piece? (Half-life period of $^{14}C$ is $5730$ years)

A
$0.125$
B
$0.25$
C
$0.5$
D
$0.75$

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Nuclear Chemistry

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Rate of decay and Half-life

An element has a half-life of $1600 \ years$. The fraction of the mass left after $6400 \ years$ will be:

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Decay of $_{92}U^{235}$ is $...$ order reaction.

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$A$ radioactive sample has a half-life of $1500 \ years$. $A$ sealed tube containing $1 \ g$ of the sample will contain after $3000 \ years$:

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$87.5\%$ decomposition of a radioactive substance completes in $3$ hours. What is the half-life of that substance?

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$A$ wood piece is $11460$ years old. What is the fraction of $^{14}C$ activity left in the piece? (Half-life period of $^{14}C$ is $5730$ years)

Similar Questions

An element has a half-life of $1600 \ years$. The fraction of the mass left after $6400 \ years$ will be:

Decay of $_{92}U^{235}$ is $...$ order reaction.

The half-life of $_{92}U^{238}$ is $4.5 \times 10^9$ years. After how many years,the amount of $_{92}U^{238}$ will be reduced to half of its present amount?

$A$ radioactive sample has a half-life of $1500 \ years$. $A$ sealed tube containing $1 \ g$ of the sample will contain after $3000 \ years$:

$87.5\%$ decomposition of a radioactive substance completes in $3$ hours. What is the half-life of that substance?

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