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Question

(B) The reaction involves the selective reduction of a ketone group to an alcohol group in the presence of a nitro group $(-NO_2)$.$NaBH_4$ (Sodium bo

Vedclass · Accepted Answer

$NaBH_4$

Vedclass · Answer

(B) The reaction involves the selective reduction of a ketone group to an alcohol group in the presence of a nitro group $(-NO_2)$.$NaBH_4$ (Sodium borohydride) is a selective reducing agent that reduces aldehydes and ketones to alcohols but does not reduce the nitro group $(-NO_2)$.$LiAlH_4$ and $H_2/Ni$ are strong reducing agents that would reduce both the ketone and the nitro group.Therefore,$NaBH_4$ is the correct reagent.

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Similar Questions

When aldehydes or ketones are treated with $C_6H_5-NH-NH_2$ (phenylhydrazine),the product formed is:

$CaOCl_2 + H_2O \longrightarrow Ca(OH)_2 + X$
$X + CH_3CHO \longrightarrow Y$
$Y + Ca(OH)_2 \longrightarrow CHCl_3$
What is '$Y$'?

Which of the following does not give a stable product with water?

Which of the following compounds undergoes aldol condensation?

$CH_3CHO \xrightarrow{LiAlH_4} CH_3CH_2OH$
Which nucleophile is added in this reaction?

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