Acceleration of a particle changes when:

  • A
    Direction of velocity changes
  • B
    Magnitude of velocity changes
  • C
    Both of the above
  • D
    Speed changes

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Similar Questions

$A$ particle is moving in a straight line such that its velocity is increasing at $5\,m/s$ per meter. The acceleration of the particle is .......... $m/s^2$ at a point where its velocity is $20\,m/s$.

Match the following columns.
Column $I$Column $II$
$(A)$ $\frac{dv}{dt}$$(p)$ Acceleration
$(B)$ $\frac{d|v|}{dt}$$(q)$ Magnitude of acceleration
$(C)$ $\frac{dr}{dt}$$(r)$ Velocity
$(D)$ $\left|\frac{dr}{dt}\right|$$(s)$ Magnitude of velocity

At any instant,the velocity and acceleration of a particle moving along a straight line are $v$ and $a$. The speed of the particle is increasing if

The velocity of a particle is given as $\vec{v} = -x\hat{i} + 2y\hat{j} - z\hat{k} \text{ m/s}$. The magnitude of acceleration at point $(1, 2, 4)$ is . . . . . . $\text{m/s}^2$.

$A$ particle starts from rest. Its acceleration $a$ versus time $t$ is shown in the figure. The maximum speed of the particle will be (in $m/s$)

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