Accomplish the following conversions:
$(i)$ Nitrobenzene to benzoic acid
$(ii)$ Benzene to $m-$bromophenol
$(iii)$ Benzoic acid to aniline
$(iv)$ Aniline to $2,4,6-$tribromofluorobenzene
$(v)$ Benzyl chloride to $2-$phenylethanamine
$(vi)$ Chlorobenzene to $p-$chloroaniline
$(vii)$ Aniline to $p-$bromoaniline
$(viii)$ Benzamide to toluene
$(ix)$ Aniline to benzyl alcohol.

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(N/A) $(i)$ Nitrobenzene $\xrightarrow{Sn/HCl}$ Aniline $\xrightarrow{NaNO_2/HCl, 0-5^{\circ}C}$ Benzenediazonium chloride $\xrightarrow{CuCN}$ Benzonitrile $\xrightarrow{H_3O^+}$ Benzoic acid.
$(ii)$ Benzene $\xrightarrow{HNO_3/H_2SO_4}$ Nitrobenzene $\xrightarrow{Br_2/FeBr_3}$ $m-$Bromonitrobenzene $\xrightarrow{Sn/HCl}$ $m-$Bromoaniline $\xrightarrow{NaNO_2/HCl, 0-5^{\circ}C}$ $m-$Bromobenzenediazonium chloride $\xrightarrow{H_2O, \Delta}$ $m-$Bromophenol.
$(iii)$ Benzoic acid $\xrightarrow{NH_3, \Delta}$ Benzamide $\xrightarrow{Br_2/KOH}$ Aniline.
$(iv)$ Aniline $\xrightarrow{Br_2/H_2O}$ $2,4,6-$Tribromoaniline $\xrightarrow{NaNO_2/HCl, 0-5^{\circ}C}$ $2,4,6-$Tribromobenzenediazonium chloride $\xrightarrow{HBF_4, \Delta}$ $2,4,6-$Tribromofluorobenzene.
$(v)$ Benzyl chloride $\xrightarrow{KCN}$ Phenylacetonitrile $\xrightarrow{LiAlH_4}$ $2-$Phenylethanamine.
$(vi)$ Chlorobenzene $\xrightarrow{HNO_3/H_2SO_4}$ $p-$Nitrochlorobenzene $\xrightarrow{Sn/HCl}$ $p-$Chloroaniline.
$(vii)$ Aniline $\xrightarrow{(CH_3CO)_2O/Pyridine}$ Acetanilide $\xrightarrow{Br_2/CH_3COOH}$ $p-$Bromoacetanilide $\xrightarrow{H_3O^+}$ $p-$Bromoaniline.
$(viii)$ Benzamide $\xrightarrow{LiAlH_4}$ Benzylamine $\xrightarrow{NaNO_2/HCl}$ Benzyl alcohol $\xrightarrow{PCl_5}$ Benzyl chloride $\xrightarrow{Mg/ether, then H_2O}$ Toluene.
$(ix)$ Aniline $\xrightarrow{NaNO_2/HCl, 0-5^{\circ}C}$ Benzenediazonium chloride $\xrightarrow{CuCN}$ Benzonitrile $\xrightarrow{LiAlH_4}$ Benzylamine $\xrightarrow{HNO_2}$ Benzyl alcohol.

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In the given reaction,$A$ is:
$A$ $\xrightarrow{\text{Reduction}} B$ $\xrightarrow{HNO_2} C_2H_5OH$

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Which of the following compounds can form alcohol with $NaNO_2/HCl$?

Match the compounds given in List-$I$ with the items given in List-$II$.
List-$I$ List-$II$
$I.$ Benzenesulphonyl Chloride $A.$ Zwitterion
$II.$ Sulphanilic acid $B.$ Hinsberg reagent
$III.$ Alkyl Diazonium salts $C.$ Dyes
$IV.$ Aryl Diazonium salts $D.$ Conversion to alcohols

Match List-$I$ with List-$II$:
List-$I$ List-$II$
$A$. Benzenesulphonyl chloride $I$. Test for primary amines
$B$. Hoffmann bromamide reaction $II$. Anti Saytzeff
$C$. Carbylamine reaction $III$. Hinsberg reagent
$D$. Hoffmann orientation $IV$. Known reaction of isocyanates

Choose the correct answer from the options given below.

Given below are some nitrogen-containing compounds. Each of them is treated with $HCl$ separately. $1.0 \ g$ of the most basic compound will consume $........$ $mg$ of $HCl$. ($Given$ molar mass in $g \ mol^{-1}$: $C:12, H:1, O:16, Cl:35.5$)

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