According to CIP sequence rule,the correct ar | vedclass

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(B) According to the $CIP$ (Cahn-Ingold-Prelog) sequence rule,priority is assigned based on the atomic number of the atom directly attached to the chi

Vedclass · Accepted Answer

$-OH > -COOH > -CHO > -CH_2-OH$

Vedclass · Answer

(B) According to the $CIP$ (Cahn-Ingold-Prelog) sequence rule,priority is assigned based on the atomic number of the atom directly attached to the chiral center.$1$. Comparing the atoms directly attached: $-OH$ (Oxygen,$Z=8$) has the highest priority.$2$. For the remaining groups,we look at the next atoms:$-COOH$ is $-C(=O)OH$,which is equivalent to $-C(O,O,O)OH$.$-CHO$ is $-C(=O)H$,which is equivalent to $-C(O,O,H)H$.$-CH_2-OH$ is $-C(O,H,H)H$.$3$. Comparing the atoms attached to the carbon: The priority order is $-COOH > -CHO > -CH_2-OH$.Thus,the correct decreasing order of priority is $-OH > -COOH > -CHO > -CH_2-OH$.

According to $CIP$ sequence rule,the correct arrangement in order of decreasing priority is :-

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