According to Cahn-Ingold-Prelog sequence rule | vedclass

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(A) According to $Cahn-Ingold-Prelog$ sequence rules,the priority of groups is decided by the atomic number of the atoms directly attached to the chir

Vedclass · Accepted Answer

$-OH > -COOH > -CHO > -CH_2OH$

Vedclass · Answer

(A) According to $Cahn-Ingold-Prelog$ sequence rules,the priority of groups is decided by the atomic number of the atoms directly attached to the chiral center.$1$. The atom with the highest atomic number gets the highest priority. Here,$O$ (atomic number $8$) has higher priority than $C$ (atomic number $6$). Thus,$-OH$ is first.$2$. For the remaining carbon-containing groups,we look at the atoms attached to the first carbon: $-COOH$ ($C$ bonded to $O, O, O$),$-CHO$ ($C$ bonded to $O, O, H$),and $-CH_2OH$ ($C$ bonded to $O, H, H$).$3$. Comparing these,the priority order is $-COOH > -CHO > -CH_2OH$.$4$. Therefore,the overall order is $-OH > -COOH > -CHO > -CH_2OH$.

According to $Cahn-Ingold-Prelog$ sequence rules,the correct order of priority for the given groups is

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