According to the IUPAC system,the given compo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. Identify the principal functional group: The carboxylic acid $(-COOH)$ group has the highest priority,so the parent chain is a butanoic acid

Vedclass · Accepted Answer

$4-(4'-$hydroxycyclohex$-2'-$enyl)$-3-$methylbutanoic acid

Vedclass · Answer

(B) $1$. Identify the principal functional group: The carboxylic acid $(-COOH)$ group has the highest priority,so the parent chain is a butanoic acid derivative.$2$. Number the parent chain: Start numbering from the carbon of the $-COOH$ group as $C-1$. The chain is $C1-C2-C3(CH_3)-C4$.$3$. Identify the substituent: At position $C-4$,there is a cyclohexenyl ring. Number the ring starting from the point of attachment to the main chain as $1'$. The double bond is at $2'$ and the hydroxyl group is at $4'$. Thus,the substituent is $4'-$hydroxycyclohex$-2'-$enyl.$4$. Combine the parts: The compound is $4-(4'-$hydroxycyclohex$-2'-$enyl)$-3-$methylbutanoic acid.

According to the $IUPAC$ system,the given compound is named as:

Similar Questions

The $IUPAC$ name of the following compound is $CH_3-CH(CH(CH_3)_2)-CH_2-CH_2-CH_3$.

Give the $IUPAC$ name of $(CH_3)_3CCH(CH_3)CH_2CH_3$.

Which is incorrect numbering in the following compounds as per $IUPAC$ rules?

The $IUPAC$ name of the compound is:

The $IUPAC$ name of the given compound is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module