According to molecular orbital theory,the tot | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The molecular orbital electronic configuration of $O_2$ ($16$ electrons) is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(C) The molecular orbital electronic configuration of $O_2$ ($16$ electrons) is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2, \pi 2p_y^2, \pi^* 2p_x^1, \pi^* 2p_y^1$. Bonding molecular orbitals are those without an asterisk $(*)$. The bonding orbitals are $\sigma 1s, \sigma 2s, \sigma 2p_z, \pi 2p_x, \pi 2p_y$. Each of these $5$ orbitals contains $2$ electrons,totaling $10$ bonding electrons. Therefore,the number of bonding electron pairs is $10 / 2 = 5$.

List-$I$	List-$II$
$(1)$ ${\rm{NO}}$	$(A)$ $1.5$
$(2)$ ${\rm{CO}}$	$(B)$ $2.0$
$(3)$ ${\rm{O}}_2^-$	$(C)$ $2.5$
$(4)$ ${\rm{O}}_2$	$(D)$ $3.0$

According to molecular orbital theory,the total number of bonding electron pairs in $O_2$ is

Similar Questions

Which of the following molecules has two unpaired $e^-$ with a bond order equal to $2$?

If $Hund's$ Rule does not hold good,then which of the following pairs is diamagnetic?

Two homo-diatomic molecules $X_2$ and $Y_2$ have the same bond order. Then,select the $CORRECT$ statement.

Match the species given in List-$I$ with their bond orders given in List-$II$.

List-$I$ List-$II$

$(1)$ ${\rm{NO}}$ $(A)$ $1.5$

$(2)$ ${\rm{CO}}$ $(B)$ $2.0$

$(3)$ ${\rm{O}}_2^-$ $(C)$ $2.5$

$(4)$ ${\rm{O}}_2$ $(D)$ $3.0$

Which of the following species has a bond order of $1.5$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module