According to Moseley's law,the frequency of a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Moseley's law states that the frequency $
u$ of a characteristic $X$-ray spectral line is given by the relation: $\sqrt{
u} = a(Z - b)$.Here,$Z$

Vedclass · Accepted Answer

Square of the atomic number of the element

Vedclass · Answer

(B) Moseley's law states that the frequency $
u$ of a characteristic $X$-ray spectral line is given by the relation: $\sqrt{
u} = a(Z - b)$.Here,$Z$ is the atomic number of the element,and $a$ and $b$ are constants that depend on the specific type of spectral line (e.g.,$K$,$L$,etc.).Squaring both sides of the equation,we get: $
u = a^2(Z - b)^2$.Since $b$ is a screening constant and is typically small compared to $Z$ for high-$Z$ elements,the frequency $
u$ is directly proportional to the square of the atomic number $(Z^2)$.Therefore,the frequency varies as the square of the atomic number of the element.

According to Moseley's law,the frequency of a spectral line in the $X$-ray spectrum varies as:

Similar Questions

The Compton effect is associated with

The $K_{\alpha}$ characteristic $X$-ray refers to the transition:

When cathode rays strike a metal target with a high melting point and high atomic number,what is produced?

The structure of solids is investigated by using

If the series limit of the Balmer series for hydrogen is $3646 \ \mathring{A}$,calculate the atomic number $(Z)$ of the element which gives an $X$-ray wavelength of the $K_{\alpha}$ line as $1.0 \ \mathring{A}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module