Acetaldehyde when treated with dilute $NaOH$ gives:

The major product $(P)$ in the following reaction is $:$

Which of the following compounds responds to both iodoform test and Fehling's test?

Reduction of which compound gives an optically active alcohol?

An organic compound $A$ has the molecular formula $C_3H_6O$. It gives the iodoform test. When it is saturated with $HCl$,it gives a compound $B$ with the molecular formula $C_9H_{14}O$. What are $A$ and $B$ respectively?

$CH_3-CHO$ $\xrightarrow{HCN} (A)$ $\xrightarrow{H_3O^{+}} (B)$ $\xrightarrow{\Delta} (C)$ $\xrightarrow{LiAlH_4} (D)$ $\xrightarrow{HIO_4} HCHO + (E)$. Compound $(C)$ can show geometrical isomerism. Product $(E)$ of the reaction will be: