Addition of HI on the double bond of propene | vedclass

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Question

(A) $HI 	o H^{+} + I^{-}$$CH_3-CH=CH_2 + H^{+} 	o CH_3-CH_2-CH_2^{+}$ ($1^o$ carbonium ion,less stable) and $CH_3-CH^{+}-CH_3$ ($2^o$ carbonium ion,

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$A$ more stable carbonium ion

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(A) $HI 	o H^{+} + I^{-}$$CH_3-CH=CH_2 + H^{+} 	o CH_3-CH_2-CH_2^{+}$ ($1^o$ carbonium ion,less stable) and $CH_3-CH^{+}-CH_3$ ($2^o$ carbonium ion,more stable).The reaction proceeds through the formation of a more stable $2^o$ carbonium ion intermediate.$CH_3-CH^{+}-CH_3 + I^{-} 	o CH_3-CH(I)-CH_3$ (isopropyl iodide,major product).

Addition of $HI$ on the double bond of propene yields isopropyl iodide and not $n$-propyl iodide as the major product. This is because the addition proceeds through

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