Aditya can row with the stream at 10 text{ km | vedclass

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(C) Let the speed of the boat in still water be $x 	ext{ km/h}$ and the speed of the stream be $y 	ext{ km/h}$.When rowing with the stream (downstre

Vedclass · Accepted Answer

$8$

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(C) Let the speed of the boat in still water be $x 	ext{ km/h}$ and the speed of the stream be $y 	ext{ km/h}$.When rowing with the stream (downstream),the effective speed is $(x + y) 	ext{ km/h}$.Given,$x + y = 10 	ext{ km/h} \quad \dots(1)$When rowing against the stream (upstream),the effective speed is $(x - y) 	ext{ km/h}$.Given,$x - y = 6 	ext{ km/h} \quad \dots(2)$Adding equation $(1)$ and $(2)$:$(x + y) + (x - y) = 10 + 6$$2x = 16$$x = 8 	ext{ km/h}$Therefore,Aditya's speed in still water is $8 	ext{ km/h}$.

Aditya can row with the stream at $10 \text{ km/h}$ and against the stream at $6 \text{ km/h}$. His speed in still water is .......... $\text{km/h}$.

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