Adsorption of a gas follows Freundlich adsorp | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The Freundlich adsorption isotherm is given by the equation $\frac{x}{m} = K \cdot p^{1/n}$,where $K$ and $n$ are constants that depend on the nat

Vedclass · Accepted Answer

Vedclass · Answer

(C) The Freundlich adsorption isotherm is given by the equation $\frac{x}{m} = K \cdot p^{1/n}$,where $K$ and $n$ are constants that depend on the nature of the adsorbent and the gas at a particular temperature.Adsorption is an exothermic process. According to Le Chatelier's principle,for an exothermic process,an increase in temperature decreases the extent of adsorption.Therefore,at a constant pressure,the amount of gas adsorbed $(\frac{x}{m})$ decreases as the temperature increases.This means that the curve for a lower temperature will lie above the curve for a higher temperature.Comparing the given options,the plot where $\frac{x}{m}$ is highest for $200 \ K$ and lowest for $270 \ K$ is the correct representation.

Adsorption of a gas follows Freundlich adsorption isotherm. If $x$ is the mass of the gas adsorbed on mass $m$ of the adsorbent,the correct plot of $\frac{x}{m}$ versus $p$ is:

Similar Questions

Which of the following is not a favourable condition for physical adsorption?

Which of the following statements is $NOT$ applicable to chemisorption?

Which forces are involved in physical adsorption?

The volumes of gases $H_2, CH_4, CO_2$ and $NH_3$ adsorbed by $1 \ g$ of charcoal at $288 \ K$ are in the order:

In the process of adsorption,which of the following values is less than zero?

Vedclass Test Series

Exam Paper Generator

Online Exam Module