An organic compound has 42.1 % carbon,6.4 % h | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. Calculate the percentage of oxygen: $100 - (42.1 + 6.4) = 51.5 \%$. $2$. Calculate the number of moles of each element in $100 \ g$ of the co

Vedclass · Accepted Answer

$C_{12}H_{22}O_{11}$

Vedclass · Answer

(D) $1$. Calculate the percentage of oxygen: $100 - (42.1 + 6.4) = 51.5 \%$. $2$. Calculate the number of moles of each element in $100 \ g$ of the compound: $n_C = \frac{42.1}{12} \approx 3.51$,$n_H = \frac{6.4}{1} = 6.4$,$n_O = \frac{51.5}{16} \approx 3.22$. $3$. Determine the empirical formula ratio: $C : H : O = \frac{3.51}{3.22} : \frac{6.4}{3.22} : \frac{3.22}{3.22} \approx 1.09 : 1.99 : 1 \approx 1.1 : 2 : 1$. $4$. Multiplying by $10$ gives $C_{11}H_{20}O_{10}$ (Empirical mass $\approx 312$). $5$. Given molecular weight is $342$. For $C_{12}H_{22}O_{11}$,molecular weight $= (12 	imes 12) + (22 	imes 1) + (11 	imes 16) = 144 + 22 + 176 = 342$. $6$. Thus,the molecular formula is $C_{12}H_{22}O_{11}$.

An organic compound has $42.1 \%$ carbon,$6.4 \%$ hydrogen and the remainder is oxygen. If its molecular weight is $342$,then its molecular formula is:

Similar Questions

An organic compound contains $78\%$ (by $wt.$) carbon and the remaining percentage of hydrogen. The correct option for the empirical formula of this compound is: [Atomic $wt.$ of $C$ is $12$,$H$ is $1$]

By usual analysis, $1.00 \ g$ of compound $(X)$ gave $1.79 \ g$ of magnesium pyrophosphate. The percentage of phosphorus in compound $(X)$ is: (nearest integer)
(Given, molar mass in $g \ mol^{-1}$; $O=16, Mg=24, P=31$)

Actual number of atoms of different elements present in a molecule of a compound is given by

$A$ gas is found to have a formula $[CO]_x$. If its vapour density is $70$,the value of $x$ is

If $0.0833 \ mol$ of a carbohydrate contains $1 \ g$ of hydrogen and its empirical formula is $CH_2O$,determine its molecular formula.

Vedclass Test Series

Exam Paper Generator

Online Exam Module