All $Zn(II)$ compounds are white because
- A$Zn^{2+}$ has a $d^{10}$ configuration and the $d$-subshell is full
- B$Zn^{2+}$ shows $d-d$ transition
- C$Zn^{2+}$ has no electron in the $4s$-subshell
- D$Zn$ is not a transition element
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