All electromagnetic waves transport energy in the negative $z$ direction. At a certain point and time,the direction of the electric field of the wave is along the positive $y$ direction. What will be the direction of the magnetic field of the wave at that point and instant?

The magnetic field of a plane electromagnetic wave is $\overrightarrow{B} = 3 \times 10^{-8} \sin [200 \pi(y + ct)] \hat{i} \, T$,where $c = 3 \times 10^{8} \, m/s$ is the speed of light. The corresponding electric field is:

If the electric field intensity of a uniform plane electromagnetic wave is given as $E = -301.6 \sin (kz - \omega t) \hat{a}_{x} + 452.4 \sin (kz - \omega t) \hat{a}_{y} \text{ V/m}$. Then,the magnetic intensity $H$ of this wave in $\text{A/m}$ will be (Given: Speed of light in vacuum $c = 3 \times 10^{8} \text{ m/s}$,permeability of vacuum $\mu_{0} = 4\pi \times 10^{-7} \text{ N/A}^{2}$)

The magnetic field in a plane electromagnetic wave is given by $B_y = (3.5 \times 10^{-7}) \sin (1.5 \times 10^3 x + 0.5 \times 10^{11} t) \ T$. The corresponding electric field will be:

$A$ plane electromagnetic wave propagating in the direction of the unit vector $\hat{n}$ with a speed $c$ is described by electric and magnetic field vectors $E$ and $B$,respectively. Which of the following relations (in $SI$ units) between $E$ and $B$ can be ruled out on dimensional grounds alone?

In a two-wire transmission line,the power flows .......