Allyl chloride is hydrolysed more readily than $n-$propyl chloride. Why?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Allyl chloride $(CH_2=CH-CH_2Cl)$ undergoes hydrolysis more readily than $n-$propyl chloride $(CH_3-CH_2-CH_2Cl)$ because the carbocation formed from allyl chloride,which is the allyl carbocation $(CH_2=CH-CH_2^+)$,is stabilized by resonance.
The resonance structures are:
$[CH_2=CH-CH_2^+ \leftrightarrow ^+CH_2-CH=CH_2]$
In contrast,the carbocation formed from $n-$propyl chloride is a primary carbocation $(CH_3-CH_2-CH_2^+)$,which lacks such resonance stabilization,making it less stable and thus less reactive towards hydrolysis.

Explore More

Similar Questions

The correct order of $C-X$ bond polarity is:

The major product $(A)$ is:

The major product of the following reaction is:

Which of the following statements about the $S_{N}2$ reaction mechanism is/are true?

In solvolysis of $1,2$-dimethylpropyl $p$-toluenesulfonate in acetic acid at $75\,^oC$,how many (alkene + substitution) products will be formed?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo