Aluminium $(III)$ chloride forms a dimer because aluminium
- Abelongs to boron family.
- Bhas a very high ionisation enthalpy.
- Ccan have higher coordination number.
- Dis next to magnesium.
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Similar Questions
Boron fluoride exists as $BF_3$ but boron hydride does not exist as $BH_3$. Give reason. In which form does it exist? Explain its structure.
Medium
View SolutionWhat are the approximate $H-B-H$ bond angles in diborane $(B_2H_6)$?
Easy
View SolutionThe incorrect statement regarding '$X$' in the given reaction is $BF_3 + LiAlH_4 \xrightarrow{\text{Ether}} (X) + LiF + AlF_3$.
Medium
View SolutionMatch the following:
Column $I$ Column $II$ $A$. $Bi^{3+} \longrightarrow (BiO)^{+}$ $P$. Heat $B$. $[AlO_2]^{-} \longrightarrow Al(OH)_3$ $Q$. Hydrolysis $C$. $SiO_4^{4-} \longrightarrow Si_2O_7^{6-}$ $R$. Acidification $D$. $(B_4O_7^{2-}) \longrightarrow [B(OH)_3]$ $S$. Dilution by water
| Column $I$ | Column $II$ |
| $A$. $Bi^{3+} \longrightarrow (BiO)^{+}$ | $P$. Heat |
| $B$. $[AlO_2]^{-} \longrightarrow Al(OH)_3$ | $Q$. Hydrolysis |
| $C$. $SiO_4^{4-} \longrightarrow Si_2O_7^{6-}$ | $R$. Acidification |
| $D$. $(B_4O_7^{2-}) \longrightarrow [B(OH)_3]$ | $S$. Dilution by water |
In diborane $(B_2H_6)$,the number of $2$-centre-$2$-electron bonds and $3$-centre-$2$-electron bonds respectively are:
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