Aluminium reacts with $NaOH$ and forms compound '$X$'. If the coordination number of aluminium in '$X$' is $6$,the correct formula of $X$ is
- A$[Al(H_2O)_4(OH)_2]^{+}$
- B$[Al(H_2O)_3(OH)_3]$
- C$[Al(H_2O)_2(OH)_4]^{-}$
- D$[Al(H_2O)_6](OH)_3$
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