Among Cl^{-},Br^{-},and I^{-},the correct ord | vedclass

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(C) The ease of oxidation of halide ions to their corresponding dihalogens depends on their standard oxidation potentials. The standard oxidation pote

Vedclass · Accepted Answer

$I^{-} > Br^{-} > Cl^{-}$

Vedclass · Answer

(C) The ease of oxidation of halide ions to their corresponding dihalogens depends on their standard oxidation potentials. The standard oxidation potential values are: $2I^{-} \rightarrow I_2 + 2e^{-}$ $(E^o_{ox} = -0.54 \ V)$ $2Br^{-} \rightarrow Br_2 + 2e^{-}$ $(E^o_{ox} = -1.07 \ V)$ $2Cl^{-} \rightarrow Cl_2 + 2e^{-}$ $(E^o_{ox} = -1.36 \ V)$ $A$ higher (less negative) oxidation potential indicates a greater tendency to undergo oxidation. Therefore,the order of ease of oxidation is $I^{-} > Br^{-} > Cl^{-}$.

Among $Cl^{-}$,$Br^{-}$,and $I^{-}$,the correct order for being oxidized to dihalogen is:

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