Among (i) [Co(NH_3)_6]Cl_3,(ii) [Ni(NH_3)_6]C | vedclass

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(A) $(i) [Co(NH_3)_6]Cl_3$: $Co^{3+}$ is $3d^6$. $NH_3$ is a strong field ligand,causing pairing of electrons. All $6$ electrons are paired,so it is d

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$(i)$

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(A) $(i) [Co(NH_3)_6]Cl_3$: $Co^{3+}$ is $3d^6$. $NH_3$ is a strong field ligand,causing pairing of electrons. All $6$ electrons are paired,so it is diamagnetic.$(ii) [Ni(NH_3)_6]Cl_2$: $Ni^{2+}$ is $3d^8$. It has $2$ unpaired electrons,so it is paramagnetic.$(iii) [Cr(H_2O)_6]Cl_3$: $Cr^{3+}$ is $3d^3$. It has $3$ unpaired electrons,so it is paramagnetic.$(iv) [Fe(H_2O)_6]Cl_2$: $Fe^{2+}$ is $3d^6$. $H_2O$ is a weak field ligand,so it has $4$ unpaired electrons,making it paramagnetic.

List-$I$	List-$II$
$A$. $[Fe(H_2O)_6]^{2+}$	$P$. $0$
$B$. $[Fe(H_2O)_6]^{3+}$	$Q$. $1$
$C$. $[Fe(CN)_6]^{4-}$	$R$. $2$
$D$. $[Fe(CN)_6]^{3-}$	$S$. $4$
$E$. $[Ni(H_2O)_4]^{2+}$	$T$. $5$

Among $(i) [Co(NH_3)_6]Cl_3$,$(ii) [Ni(NH_3)_6]Cl_2$,$(iii) [Cr(H_2O)_6]Cl_3$,$(iv) [Fe(H_2O)_6]Cl_2$,the complex which is diamagnetic is $....$

Similar Questions

Which of the following compounds does not show optical activity?

Match the complex ion (in List-$I$) with the number of unpaired electrons (in List-$II$):

List-$I$ List-$II$

$A$. $[Fe(H_2O)_6]^{2+}$ $P$. $0$

$B$. $[Fe(H_2O)_6]^{3+}$ $Q$. $1$

$C$. $[Fe(CN)_6]^{4-}$ $R$. $2$

$D$. $[Fe(CN)_6]^{3-}$ $S$. $4$

$E$. $[Ni(H_2O)_4]^{2+}$ $T$. $5$

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Reason : It has a plane of symmetry.

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Which of the following statements is not true about the complex ion $[Cr(en)_2Cl_2]^+$?

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