Among B_2H_6, B_3N_3H_6, N_2O, N_2O_4, H_2S_2 | vedclass

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(B) Let us analyze the structures of the given molecules to identify those with a covalent bond between two atoms of the same kind:$1$. $B_2H_6$ (Dibo

Vedclass · Accepted Answer

$4$

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(B) Let us analyze the structures of the given molecules to identify those with a covalent bond between two atoms of the same kind:$1$. $B_2H_6$ (Diborane): Contains $B-H-B$ bridge bonds. There is no $B-B$ bond.$2$. $B_3N_3H_6$ (Borazine): Contains $B-N$ bonds. There is no $B-B$ or $N-N$ bond.$3$. $N_2O$: The structure is $N \equiv N \rightarrow O$. It contains an $N-N$ bond.$4$. $N_2O_4$: The structure is $O_2N-NO_2$. It contains an $N-N$ bond.$5$. $H_2S_2O_3$ (Thiosulfuric acid): The structure contains an $S-S$ bond.$6$. $H_2S_2O_8$ (Peroxodisulfuric acid): The structure contains an $O-O$ (peroxide) bond.Thus,the molecules containing a covalent bond between two atoms of the same kind are $N_2O, N_2O_4, H_2S_2O_3$,and $H_2S_2O_8$.The total number of such molecules is $4$.

Among $B_2H_6, B_3N_3H_6, N_2O, N_2O_4, H_2S_2O_3$ and $H_2S_2O_8$,the total number of molecules containing a covalent bond between two atoms of the same kind is . . . .

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