Among V, Cr, Zn, Fe,the metal having the lowe | vedclass

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(C) The enthalpy of atomization depends on the strength of metallic bonding,which is determined by the number of unpaired electrons in the $d$-orbital

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$Zn$

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(C) The enthalpy of atomization depends on the strength of metallic bonding,which is determined by the number of unpaired electrons in the $d$-orbital.$Zn$ has a $3d^{10} 4s^2$ electronic configuration.Due to the absence of unpaired electrons in the $d$-subshell,the metallic bonding in $Zn$ is the weakest among the given transition metals.Therefore,$Zn$ has the lowest enthalpy of atomization.

Among $V, Cr, Zn, Fe$,the metal having the lowest enthalpy of atomization is

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