Among the electrolytes Na_2SO_4,CaCl_2,Al_2(S | vedclass

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(C) According to the Hardy-Schulze rule,the coagulating power of an electrolyte depends on the valency of the active ion (ion with charge opposite to

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$Al_2(SO_4)_3$

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(C) According to the Hardy-Schulze rule,the coagulating power of an electrolyte depends on the valency of the active ion (ion with charge opposite to that of the sol).$Sb_2S_3$ sol is a negatively charged sol.Therefore,the coagulating power depends on the charge of the cation.The cations present in the given electrolytes are $Na^+$,$Ca^{2+}$,$Al^{3+}$,and $NH_4^+$.According to the Hardy-Schulze rule,the higher the valency of the coagulating ion,the greater is its coagulating power.Since $Al^{3+}$ has the highest charge $(+3)$,$Al_2(SO_4)_3$ is the most effective coagulating agent.

Among the electrolytes $Na_2SO_4$,$CaCl_2$,$Al_2(SO_4)_3$ and $NH_4Cl$,the most effective coagulating agent for $Sb_2S_3$ sol is

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