Among the following,the number of aromatic co | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine if a compound is aromatic,it must satisfy $H$ückel's rule: it must be planar,cyclic,fully conjugated,and contain $(4n + 2) \pi$ elect

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(A) To determine if a compound is aromatic,it must satisfy $H$ückel's rule: it must be planar,cyclic,fully conjugated,and contain $(4n + 2) \pi$ electrons,where $n = 0, 1, 2, ...$.Let us analyze the given structures:$1$. Cyclooctatetraene: Non-planar (tub-shaped),$8 \pi$ electrons. Not aromatic.$2$. Cyclopropenyl anion: $4 \pi$ electrons. Anti-aromatic.$3$. Cyclopropenyl cation: $2 \pi$ electrons $(n=0)$. Aromatic.$4$. Cyclohexadiene: Not fully conjugated. Not aromatic.$5$. Cycloheptatrienyl cation (tropylium ion): $6 \pi$ electrons $(n=1)$. Aromatic.$6$. Cyclopentadienyl cation: $4 \pi$ electrons. Anti-aromatic.$7$. Cyclopentadienyl anion: $6 \pi$ electrons $(n=1)$. Aromatic.$8$. $1,2$-dihydronaphthalene: Not fully conjugated. Not aromatic.$9$. Phenanthrene: $14 \pi$ electrons $(n=3)$. Aromatic.The aromatic compounds are: cyclopropenyl cation,cycloheptatrienyl cation,cyclopentadienyl anion,and phenanthrene.Total number of aromatic compounds = $4$.Since $4$ is not in the options,let us re-evaluate the structures provided in the image.Looking closely at the provided solution image,it identifies: cyclopropenyl cation,cycloheptatrienyl cation,cyclopentadienyl anion,and phenanthrene as aromatic. The total count is $4$. Given the options,there might be a discrepancy in the question's provided options or the image interpretation. Based on standard chemistry,the count is $4$.

Among the following,the number of aromatic compound$(s)$ is

Similar Questions

Write the sulphonation reactions of benzene.

The cyclopentadienyl anion is:

Which one of the following functional groups is not meta directing?

The major product formed in the following reaction sequence is:
$C_6H_5-CHBr-CH_2Br$ $\xrightarrow[(ii) NaNH_2]{(i) alc. KOH}$ $\xrightarrow[(iii) \text{Red hot iron tube}, 873 K]{}$

Identify the position where $E.A.S.$ (Electrophilic Aromatic Substitution) can take place in the given molecule.

Vedclass Test Series

Exam Paper Generator

Online Exam Module