Among the following,the number of compounds t | vedclass

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(A) $PCl_5$ reacts with compounds containing oxygen to form $POCl_3$ under specific conditions. Let us analyze each compound:$1$. $O_2$: Does not reac

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$4$

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(A) $PCl_5$ reacts with compounds containing oxygen to form $POCl_3$ under specific conditions. Let us analyze each compound:$1$. $O_2$: Does not react with $PCl_5$.$2$. $CO_2$: Does not react with $PCl_5$.$3$. $SO_2$: $PCl_5 + SO_2 \rightarrow POCl_3 + SOCl_2$. (Reacts)$4$. $H_2O$: $PCl_5 + H_2O \rightarrow POCl_3 + 2HCl$. (Reacts with limited water)$5$. $H_2SO_4$: $2PCl_5 + H_2SO_4 \rightarrow 2POCl_3 + SO_2Cl_2 + 2HCl$. (Reacts)$6$. $P_4O_{10}$: $6PCl_5 + P_4O_{10} \rightarrow 10POCl_3$. (Reacts)Thus,the compounds that react to give $POCl_3$ are $SO_2, H_2O, H_2SO_4$,and $P_4O_{10}$. The total number of such compounds is $4$.

Among the following,the number of compounds that can react with $PCl_5$ to give $POCl_3$ is $O_2, CO_2, SO_2, H_2O, H_2SO_4, P_4O_{10}$.

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