Among the following Cr(III) complexes,which o | vedclass

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(D) strong field ligand will cause higher crystal field splitting. This can be predicted from the relative position of a ligand in the spectrochemical

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$[Cr(CN)_6]^{3-}$

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(D) strong field ligand will cause higher crystal field splitting. This can be predicted from the relative position of a ligand in the spectrochemical series.In the given octahedral complexes of $Cr(III)$ ion,the ligands are $F^{-}$,$H_2O$,$NH_3$,and $CN^{-}$.The increasing order of their field strength in the spectrochemical series is $F^{-} Since $CN^{-}$ is the strongest field ligand among the given choices,$[Cr(CN)_6]^{3-}$ will have the highest octahedral crystal field splitting.

List-$I$ (Complex)	List-$II$ ($CFSE$ in $\Delta_0$)
$A$. $[Ti(H_2O)_6]^{2+}$	$I$. $-1.2$
$B$. $[V(H_2O)_6]^{2+}$	$II$. $-0.8$
$C$. $[Mn(H_2O)_6]^{3+}$	$III$. $-0.6$
$D$. $[Fe(H_2O)_6]^{3+}$	$IV$. $0$

Among the following $Cr(III)$ complexes,which one will have the highest octahedral crystal field splitting?

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Match List-$I$ with List-$II$:

List-$I$ (Complex) List-$II$ ($CFSE$ in $\Delta_0$)

$A$. $[Ti(H_2O)_6]^{2+}$ $I$. $-1.2$

$B$. $[V(H_2O)_6]^{2+}$ $II$. $-0.8$

$C$. $[Mn(H_2O)_6]^{3+}$ $III$. $-0.6$

$D$. $[Fe(H_2O)_6]^{3+}$ $IV$. $0$

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