Among the following complexes,the total numbe | vedclass

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(A) $Mn^{3+} (3d^4)$: In both strong and weak fields,it has unpaired electrons. Hence,$[Mn(NH_3)_6]^{3+}$ and $[MnCl_6]^{3-}$ are paramagnetic.$Fe^{3+

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(A) $Mn^{3+} (3d^4)$: In both strong and weak fields,it has unpaired electrons. Hence,$[Mn(NH_3)_6]^{3+}$ and $[MnCl_6]^{3-}$ are paramagnetic.$Fe^{3+} (3d^5)$: In both strong and weak fields,it has unpaired electrons. Hence,$[FeF_6]^{3-}$ and $[Fe(NH_3)_6]^{3+}$ are paramagnetic.$Co^{3+} (3d^6)$: $1$. $[CoF_6]^{3-}$: $F^-$ is a weak field ligand,so it forms a high-spin complex with $t_{2g}^4 e_g^2$ configuration,which is paramagnetic.$2$. $[Co(en)_3]^{3+}$: $en$ is a strong field ligand,so it forms a low-spin complex with $t_{2g}^6 e_g^0$ configuration,which is diamagnetic.Thus,only $[Co(en)_3]^{3+}$ is diamagnetic. The total number of diamagnetic species is $1$.

Among the following complexes,the total number of diamagnetic species is. . . . $[Mn(NH_3)_6]^{3+}, [MnCl_6]^{3-}, [FeF_6]^{3-}, [CoF_6]^{3-}, [Fe(NH_3)_6]^{3+}$ and $[Co(en)_3]^{3+}$
[Given,atomic number: $Mn=25, Fe=26, Co=27$; $en=H_2NCH_2CH_2NH_2$ ]

Similar Questions

Which of the following complex ions exhibits geometrical isomerism?

Arrange the following coordination compounds in the increasing order of magnetic moments. (Atomic numbers: $Mn = 25$; $Fe = 26$)
$(A)$ $[FeF_{6}]^{3-}$
$(B)$ $[Fe(CN)_{6}]^{3-}$
$(C)$ $[MnCl_{6}]^{3-}$ (high spin)
$(D)$ $[Mn(CN)_{6}]^{3-}$

The compound$(s)$ that exhibit$(s)$ geometrical isomerism is(are):
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$B$. $[Pt(en)_2]Cl_2$
$C$. $[Pt(en)_2Cl_2]Cl_2$
$D$. $[Pt(NH_3)_2Cl_2]$

Which of the following is incorrectly matched?

Which of the following will have two stereoisomeric forms?
$I. [Cr(NO_3)_3(NH_3)_3]$
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Among the following complexes,the total number of diamagnetic species is. . . . $[Mn(NH_3)_6]^{3+}, [MnCl_6]^{3-}, [FeF_6]^{3-}, [CoF_6]^{3-}, [Fe(NH_3)_6]^{3+}$ and $[Co(en)_3]^{3+}$[Given,atomic number: $Mn=25, Fe=26, Co=27$; $en=H_2NCH_2CH_2NH_2$ ]