Among the following compounds,E/Z isomerism i | vedclass

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(D) The correct answer is $(d)$.For an alkene to exhibit $E/Z$ isomerism,each carbon atom of the $C=C$ double bond must be attached to two different g

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$3$-methylpent$-2$-ene

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(D) The correct answer is $(d)$.For an alkene to exhibit $E/Z$ isomerism,each carbon atom of the $C=C$ double bond must be attached to two different groups. If either carbon atom has two identical groups,$E/Z$ isomerism is not possible.$(a)$ $2$-methylbut$-2$-ene: The $C2$ carbon is attached to two methyl groups. Since these are identical,it does not show $E/Z$ isomerism.$(b)$ $2$-methylbut$-1$-ene: The $C1$ carbon is attached to two hydrogen atoms. Since these are identical,it does not show $E/Z$ isomerism.$(c)$ $3$-methylpent$-1$-ene: The $C1$ carbon is attached to two hydrogen atoms. Since these are identical,it does not show $E/Z$ isomerism.$(d)$ $3$-methylpent$-2$-ene: The $C2$ carbon is attached to a hydrogen and a methyl group,and the $C3$ carbon is attached to a hydrogen and a sec-butyl group. Since all groups on each carbon are different,this compound exhibits $E/Z$ isomerism.

Among the following compounds,$E/Z$ isomerism is possible for

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