Among the following electrolytes,which is the | vedclass

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(C) $Fe(OH)_3$ is a positively charged sol.According to the Hardy-Schulze rule,the coagulating power of an electrolyte increases with the increase in

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$Mg_3(PO_4)_2$

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(C) $Fe(OH)_3$ is a positively charged sol.According to the Hardy-Schulze rule,the coagulating power of an electrolyte increases with the increase in the magnitude of the charge on the ion of opposite sign to that of the colloidal particle.For a positively charged $Fe(OH)_3$ sol,the coagulating ion must be negatively charged (anion).The anions provided by the electrolytes are:$Na_2SO_4 \rightarrow SO_4^{2-}$$KCl \rightarrow Cl^-$$Mg_3(PO_4)_2 \rightarrow PO_4^{3-}$$CH_3COONa \rightarrow CH_3COO^-$Since $PO_4^{3-}$ has the highest negative charge $(-3)$,$Mg_3(PO_4)_2$ is the most effective coagulating agent.

List-$I$ (Sol)	List-$II$ (Method of preparation)
$A$. $As_2S_3$	$IV$. Double decomposition
$B$. $Au$	$I$. Bredig's arc method
$C$. $S$	$II$. Oxidation
$D$. $Fe(OH)_3$	$III$. Hydrolysis

Among the following electrolytes,which is the most effective coagulating agent for $Fe(OH)_3$ sol?

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$A$. $As_2S_3$ $IV$. Double decomposition
$B$. $Au$ $I$. Bredig's arc method
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