Among the following four compounds:(i) Phenol | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The acidity of phenols is determined by the stability of the phenoxide ion formed after the loss of a proton.Electron-withdrawing groups $(EWG)$,s

Vedclass · Accepted Answer

$(iv) > (iii) > (i) > (ii)$

Vedclass · Answer

(A) The acidity of phenols is determined by the stability of the phenoxide ion formed after the loss of a proton.Electron-withdrawing groups $(EWG)$,such as $-NO_2$,stabilize the phenoxide ion through $-I$ and $-M$ effects,thereby increasing the acidity.Electron-releasing groups $(ERG)$,such as $-CH_3$,destabilize the phenoxide ion through $+I$ and $+H$ effects,thereby decreasing the acidity.Comparing the compounds:$1$. $(iv)$ Para-nitrophenol: $-NO_2$ at para position exerts both $-I$ and $-M$ effects,providing maximum stabilization.$2$. $(iii)$ Meta-nitrophenol: $-NO_2$ at meta position exerts only $-I$ effect,providing less stabilization than para.$3$. $(i)$ Phenol: Reference compound.$4$. $(ii)$ Methyl phenol: $-CH_3$ group exerts $+I$ and $+H$ effects,destabilizing the phenoxide ion.Thus,the correct order of acidity is $(iv) > (iii) > (i) > (ii)$.

Among the following four compounds:
$(i)$ Phenol
$(ii)$ Methyl phenol
$(iii)$ Meta-nitrophenol
$(iv)$ Para-nitrophenol
The acidity order is:

Similar Questions

The major product of the following reaction is:

Suppose the following reaction:
$CH_3-CH_2-OH$ $\xrightarrow{Cl_2/NaOH} A$ $\xrightarrow{\text{Phenol}/OH^-} \text{Major Product}$
The structure of the Major Product will be:

When phenol is treated with $CHCl_3$ and $NaOH$,which of the following products is obtained?

What is the product formed when sodium phenoxide reacts with $CO_2$ at $400 \ K$ temperature and $4.7 \ atm$ pressure?

Phenol is less acidic than

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Among the following four compounds:$(i)$ Phenol$(ii)$ Methyl phenol$(iii)$ Meta-nitrophenol$(iv)$ Para-nitrophenolThe acidity order is: