Among the following, the ion which will be mo | vedclass

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(A) According to the $Hardy-Schulze$ law, the coagulating power of an ion depends on the magnitude of the charge carried by the ion.$Fe(OH)_{3}$ sol i

Vedclass · Accepted Answer

$PO_{4}^{3-}$

Vedclass · Answer

(A) According to the $Hardy-Schulze$ law, the coagulating power of an ion depends on the magnitude of the charge carried by the ion.$Fe(OH)_{3}$ sol is a positively charged sol.Therefore, the ion with the highest negative charge will be most effective for its flocculation.Comparing the charges of the given ions:$PO_{4}^{3-}$ has a charge of $-3$.$SO_{4}^{2-}$ has a charge of $-2$.$SO_{3}^{2-}$ has a charge of $-2$.$NO_{3}^{-}$ has a charge of $-1$.Since $PO_{4}^{3-}$ carries the highest negative charge, it is the most effective ion for the flocculation of $Fe(OH)_{3}$ sol.

Among the following, the ion which will be more effective for flocculation of $Fe(OH)_{3}$ sol is:

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