Among the molecules O_2,KO_2,H_2O_2,F_2O_2 an | vedclass

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(D) The oxygen-oxygen bond lengths are determined by the bond order and the electronic environment.$1$. $O_2$: Bond order is $2.0$,bond length $\appro

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$KO_2$ and $F_2O_2$

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(D) The oxygen-oxygen bond lengths are determined by the bond order and the electronic environment.$1$. $O_2$: Bond order is $2.0$,bond length $\approx 121 	ext{ pm}$.$2$. $KO_2$: Contains superoxide ion $O_2^-$,bond order is $1.5$,bond length $\approx 128 	ext{ pm}$.$3$. $H_2O_2$: Contains peroxide ion $O_2^{2-}$,bond order is $1.0$,bond length $\approx 148 	ext{ pm}$.$4$. $F_2O_2$: Bond order is $1.0$,but due to the high electronegativity of $F$,the $O-O$ bond length is $\approx 122 	ext{ pm}$.$5$. $BaO_2$: Contains peroxide ion $O_2^{2-}$,bond order is $1.0$,bond length $\approx 149 	ext{ pm}$.Comparing the values,$KO_2$ $(128 	ext{ pm})$ and $F_2O_2$ $(122 	ext{ pm})$ have the most similar bond lengths among the given choices.

Among the molecules $O_2$,$KO_2$,$H_2O_2$,$F_2O_2$ and $BaO_2$,the pair that has the most similar oxygen-oxygen bond length is:

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