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(C) The boiling point of a compound depends on the intermolecular forces present. Propan$-1-$ol $(CH_3CH_2CH_2OH)$,Butan$-1-$ol $(CH_3CH_2CH_2CH_2OH)$

Vedclass · Accepted Answer

Ethoxyethane

Vedclass · Answer

(C) The boiling point of a compound depends on the intermolecular forces present. Propan$-1-$ol $(CH_3CH_2CH_2OH)$,Butan$-1-$ol $(CH_3CH_2CH_2CH_2OH)$,and Propane$-1,2-$diol $(CH_3CH(OH)CH_2OH)$ are alcohols and can form intermolecular hydrogen bonds,which significantly increase their boiling points. Ethoxyethane $(CH_3CH_2OCH_2CH_3)$ is an ether and cannot form intermolecular hydrogen bonds among its own molecules. Therefore,ethoxyethane has the weakest intermolecular forces (dipole-dipole interactions) compared to the alcohols,resulting in the lowest boiling point.

Amongst the following compounds,the compound having the lowest boiling point is

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$(i)$ $CH_3-CH_2-CH(CH_3)-CH_2-O-CH_2-CH_3$
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$(iii)$ $C_6H_5-CH_2-O-C_6H_5$

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