An $npn$ transistor operates as a common emitter amplifier,with a power gain of $60\, dB$. The input circuit resistance is $100\,\Omega$ and the output load resistance is $10\, k\Omega$. The common emitter current gain $\beta$ is:

When $n-p-n$ transistor is used as an amplifier :

Identify the terminals of this $BJT$ and the type of $BJT$ $(NPN$ or $PNP)$. The multimeter is set to diode test mode (indicated by the symbol),and the black probe is connected to the $COM$ port while the red probe is connected to the $V\Omega$ port. Based on the connections shown in the image,determine the terminal configuration (from left to right) and the transistor type.

An $N-P-N$ transistor conducts when:

In a transistor, if $\frac{I_C}{I_E} = \alpha$ and $\frac{I_C}{I_B} = \beta$. If $\alpha$ varies between $\frac{20}{21}$ and $\frac{100}{101}$, then the value of $\beta$ lies between:

An $n-p-n$ transistor is connected in common-emitter configuration as shown in the figure. If the collector current is $5 \text{ mA}$,$V_{BE} = 0.6 \text{ V}$,$V_{CE} = 3 \text{ V}$,and the common-emitter current amplification factor $\beta = 50$,then the values of $R_1$ and $R_2$ are respectively.