An AC voltage V = 5 cos(1000t) text{ V} is ap | vedclass

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(B) The given $AC$ voltage is $V = V_m \cos(\omega t)$, where $V_m = 5 	ext{ V}$ and $\omega = 1000 	ext{ rad/s}$.For an $L-R$ circuit, the impedanc

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(B) The given $AC$ voltage is $V = V_m \cos(\omega t)$, where $V_m = 5 	ext{ V}$ and $\omega = 1000 	ext{ rad/s}$.For an $L-R$ circuit, the impedance $Z$ is given by $Z = \sqrt{R^2 + X_L^2}$, where $X_L = \omega L$.Given $L = 3 	ext{ mH} = 3 	imes 10^{-3} 	ext{ H}$ and $R = 4 	ext{ } \Omega$.Calculating inductive reactance: $X_L = 1000 	imes 3 	imes 10^{-3} = 3 	ext{ } \Omega$.Calculating impedance: $Z = \sqrt{4^2 + 3^2} = \sqrt{16 + 9} = \sqrt{25} = 5 	ext{ } \Omega$.The maximum current $I_m$ is given by $I_m = \frac{V_m}{Z}$.Substituting the values: $I_m = \frac{5}{5} = 1 	ext{ A}$.

An $AC$ voltage $V = 5 \cos(1000t) \text{ V}$ is applied to an $L-R$ circuit of inductance $3 \text{ mH}$ and resistance $4 \text{ } \Omega$. The value of maximum current in the circuit is . . . . . . $A$.

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