An e.m.f. of 12 V is induced in a coil when t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The formula for the induced $e.m.f.$ in a coil due to self-induction is given by $e = L \cdot \frac{di}{dt}$.Given:Induced $e.m.f.$ $(e)$ = $12$ $

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(B) The formula for the induced $e.m.f.$ in a coil due to self-induction is given by $e = L \cdot \frac{di}{dt}$.Given:Induced $e.m.f.$ $(e)$ = $12$ $V$.Rate of change of current $(\frac{di}{dt})$ = $48$ $A/min$.First, convert the rate of change of current into $A/s$:$\frac{di}{dt} = \frac{48 	ext{ A}}{60 	ext{ s}} = 0.8 	ext{ A/s}$.Now, substitute the values into the formula:$L = \frac{e}{di/dt} = \frac{12}{0.8} = 15 	ext{ H}$.Therefore, the self-inductance of the coil is $15 	ext{ H}$.

An $e.m.f.$ of $12$ $V$ is induced in a coil when the current in it changes at the rate of $48$ $A/min$. The self-inductance of the coil is:

Similar Questions

Find out the $e.m.f.$ produced when the current changes from $0$ to $1 \, A$ in $10 \, s$,given $L = 10 \, \mu H$.

$A$ varying current in a coil changes from $10 \, A$ to $0 \, A$ in $0.5 \, s$. If the average $EMF$ induced in the coil is $220 \, V$,the self-inductance of the coil is ... $H$.

Why does the current not rise immediately in a circuit containing inductance?

Calculate the self-inductance of a very long solenoid.

$A$ $12\,V$ battery connected to a coil of resistance $6\,\Omega$ through a switch,drives a constant current in the circuit. The switch is opened in $1\,ms$. The emf induced across the coil is $20\,V$. The inductance of the coil is ........... $mH$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module