An aeroplane travels 2500 , km,1200 , km,and | vedclass

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(A) The average speed is defined as the total distance traveled divided by the total time taken.First,we calculate the time taken for each segment of

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$420$

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(A) The average speed is defined as the total distance traveled divided by the total time taken.First,we calculate the time taken for each segment of the journey using the formula: $	ext{Time} = \frac{	ext{Distance}}{	ext{Speed}}$.						Distance			Speed			Time							$2500 \, km$			$500 \, km/h$			$5 \, hrs$							$1200 \, km$			$400 \, km/h$			$3 \, hrs$							$500 \, km$			$250 \, km/h$			$2 \, hrs$							Total: $4200 \, km$			-			Total: $10 \, hrs$			Now,calculate the average speed:$	ext{Average Speed} = \frac{	ext{Total Distance}}{	ext{Total Time}} = \frac{4200 \, km}{10 \, hrs} = 420 \, km/h$.

An aeroplane travels $2500 \, km$,$1200 \, km$,and $500 \, km$ at $500 \, km/h$,$400 \, km/h$,and $250 \, km/h$ respectively. The average speed is (in $km/h$):

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