An alkane (mol. wt. = 86) on bromination give | vedclass

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(C) The molecular weight of the alkane is $86$.General formula for alkane: $C_nH_{2n+2} = 86$$12n + 2n + 2 = 86$$14n = 84$$n = 6$The alkane is $C_6H_{

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$CH_3-CH(CH_3)-CH(CH_3)-CH_3$

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(C) The molecular weight of the alkane is $86$.General formula for alkane: $C_nH_{2n+2} = 86$$12n + 2n + 2 = 86$$14n = 84$$n = 6$The alkane is $C_6H_{14}$.$2$,$3$-dimethylbutane $(CH_3-CH(CH_3)-CH(CH_3)-CH_3)$ has two types of equivalent hydrogen atoms:$1.$ Twelve $CH_3$ hydrogens are equivalent (on the four methyl groups).$2.$ Two $CH$ hydrogens are equivalent (on the two tertiary carbons).Thus,it gives only two monobromo derivatives.

An alkane (mol. wt. = $86$) on bromination gives only two monobromo derivatives (excluding stereoisomers). The alkane is

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