An alkane has a C/H ratio (by mass) of 5.1428 | vedclass

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(B) The general formula for an alkane is $C_nH_{2n+2}$.The mass ratio of $C$ to $H$ is given by $\frac{12n}{1(2n+2)} = \frac{12n}{2n+2} = \frac{6n}{n+

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$C_6H_{14}$

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(B) The general formula for an alkane is $C_nH_{2n+2}$.The mass ratio of $C$ to $H$ is given by $\frac{12n}{1(2n+2)} = \frac{12n}{2n+2} = \frac{6n}{n+1}$.Given the ratio is $5.1428$,we set up the equation:$\frac{6n}{n+1} = 5.1428$$6n = 5.1428(n + 1)$$6n = 5.1428n + 5.1428$$6n - 5.1428n = 5.1428$$0.8572n = 5.1428$$n = \frac{5.1428}{0.8572} = 6$Substituting $n = 6$ into the general formula $C_nH_{2n+2}$,we get $C_6H_{2(6)+2} = C_6H_{14}$.

An alkane has a $C/H$ ratio (by mass) of $5.1428$. Its molecular formula is

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