An alkyl halide reacts with alcoholic ammonia in a sealed tube,the product formed will be

$90 \ g$ of ethylamine on reaction with methyl chloride produces a tertiary amine as the exclusive product. The amount of methyl chloride required is:
$[\text{Given atomic masses in amu}: H=1, C=12, N=14, Cl=35.5]$ (in $g$)

Match List-$I$ with List-$II$:

List-$I$	List-$II$
$A$. Benzenesulphonyl chloride	$I$. Test for primary amines
$B$. Hoffmann bromamide reaction	$II$. Anti Saytzeff
$C$. Carbylamine reaction	$III$. Hinsberg reagent
$D$. Hoffmann orientation	$IV$. Known reaction of isocyanates

Choose the correct answer from the options given below.

The number of primary,secondary,and tertiary amines possible with the molecular formula $C_3H_9N$ is:

$STATEMENT-1$: Aniline on reaction with $NaNO_2 / HCl$ at $0^{\circ} C$ followed by coupling with $\beta$-naphthol gives a dark blue coloured precipitate.
$STATEMENT-2$: The colour of the compound formed in the reaction of aniline with $NaNO_2 / HCl$ at $0^{\circ} C$ followed by coupling with $\beta$-naphthol is due to the extended conjugation.

Rank the following compounds in order of increasing basic strength. (weakest $\to$ strongest)