An alloy of metals A,B,and C is found to have | vedclass

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(C) In a $ccp$ lattice,the number of $A$ atoms per unit cell is $8 	imes \frac{1}{8} + 6 	imes \frac{1}{2} = 4$.$B$ atoms occupy the edge centers. T

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$A_4B_3C$

Vedclass · Answer

(C) In a $ccp$ lattice,the number of $A$ atoms per unit cell is $8 	imes \frac{1}{8} + 6 	imes \frac{1}{2} = 4$.$B$ atoms occupy the edge centers. There are $12$ edges in a unit cell,and each edge center is shared by $4$ unit cells. Thus,the number of $B$ atoms is $12 	imes \frac{1}{4} = 3$.$C$ atoms are present at the body center. There is only $1$ body center per unit cell,which is not shared by any other unit cell. Thus,the number of $C$ atoms is $1 	imes 1 = 1$.Therefore,the ratio of $A:B:C$ is $4:3:1$,and the formula of the alloy is $A_4B_3C$.

An alloy of metals $A$,$B$,and $C$ is found to have $A$ constituting a $ccp$ lattice. If $B$ atoms occupy the edge centers and $C$ is present at the body center,the formula of the alloy is:

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