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Question

(C) The standard equation for alternating current is $i = i_0 \sin(\omega t)$.Comparing this with the given equation $i = 100 \sqrt{2} \sin(100 \pi t)

Vedclass · Accepted Answer

$100 \ A, 50 \ Hz$

Vedclass · Answer

(C) The standard equation for alternating current is $i = i_0 \sin(\omega t)$.Comparing this with the given equation $i = 100 \sqrt{2} \sin(100 \pi t)$,we get the peak current $i_0 = 100 \sqrt{2} \ A$ and angular frequency $\omega = 100 \pi \ rad/s$.The $	ext{RMS}$ value of current is given by $i_{rms} = \frac{i_0}{\sqrt{2}} = \frac{100 \sqrt{2}}{\sqrt{2}} = 100 \ A$.The frequency $f$ is given by $f = \frac{\omega}{2 \pi} = \frac{100 \pi}{2 \pi} = 50 \ Hz$.Thus,the $	ext{RMS}$ value is $100 \ A$ and the frequency is $50 \ Hz$.

An alternating current is represented by the equation,$i = 100 \sqrt{2} \sin(100 \pi t) \ A$. The $\text{RMS}$ value of current and the frequency of the given alternating current are:

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