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(B) The induced electromotive force $(EMF)$ in the secondary coil is given by $e = -M \frac{di}{dt}$.From the figure,the current increases from $0$ to

Vedclass · Accepted Answer

$191$

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(B) The induced electromotive force $(EMF)$ in the secondary coil is given by $e = -M \frac{di}{dt}$.From the figure,the current increases from $0$ to $1 \, A$ in a time interval of $T/4$,where $T$ is the time period of the wave.Thus,the rate of change of current is $\frac{di}{dt} = \frac{1 - 0}{T/4} = \frac{4}{T}$.The magnitude of the induced voltage is $|e| = M \left| \frac{di}{dt} ight| = 1.5 	imes \frac{4}{T} = \frac{6}{T}$.The angular frequency is $\omega = 200 \, rad/sec$. Since $\omega = \frac{2\pi}{T}$,we have $T = \frac{2\pi}{\omega} = \frac{2\pi}{200} = \frac{\pi}{100} \, s$.Substituting the value of $T$ into the expression for $|e|$,we get $|e| = \frac{6}{\pi/100} = \frac{600}{\pi} \, V$.Using $\pi \approx 3.14159$,we find $|e| \approx \frac{600}{3.14159} \approx 190.98 \, V$.Rounding to the nearest integer,we get $|e| \approx 191 \, V$.

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