An alternating voltage $v = 200 \sqrt{2} \sin(100 t)$ is connected to a $1 \mu F$ capacitor through an $A.C.$ ammeter. The reading of the ammeter shall be: (in $\text{ mA}$)

What is the phase difference between $V$ and $I$ in a circuit containing only a resistor?

In an a.c. circuit with pure capacitance $C$ and a.c. source $E = E_0 \sin \omega t$, the equation of instantaneous current is given by

An alternating voltage $e = 200 \sqrt{2} \sin(100 t) \text{ V}$ is connected to a $1 \mu F$ capacitor through an $AC$ ammeter. The reading of the ammeter is: (in $\text{ mA}$)

$A$ $120 \, V$ $AC$ source is connected across a pure inductor of inductance $0.70 \, H$. If the frequency of the source is $60 \, Hz$,the current passing through the inductor is: (in $, A$)

An alternating voltage $v(t) = 220 \sin(100 \pi t) \text{ V}$ is applied to a purely resistive load of $50 \, \Omega$. The time taken for the current to rise from zero to half of its peak value is ..... $ms$.