(A) The inductive reactance $X_L$ is given by the formula $X_L = \omega L$, where $\omega = 2 \pi f$.Substituting the value of $\omega$, we get $X_L =

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(A) The inductive reactance $X_L$ is given by the formula $X_L = \omega L$, where $\omega = 2 \pi f$.Substituting the value of $\omega$, we get $X_L = 2 \pi f L$.Given $X_L = 11 \, \Omega$ and $L = 0.07 \, H$, we can solve for frequency $f$:$f = \frac{X_L}{2 \pi L} = \frac{11}{2 \times 3.14159 \times 0.07} \approx \frac{11}{0.4398} \approx 25 \, Hz$.Thus, the frequency of the alternating voltage is $25 \, Hz$.

Class 12 Physics Alternating Current Only Inductor, Only Capacitor and Only Resistor Circuit

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An alternating voltage of $22 \, V$ is applied across an inductance coil of reactance $11 \, \Omega$. If the inductance of the coil is $0.07 \, H$, the frequency of the alternating voltage is: (in $ \, Hz$)

MHT CET 2022 All MHT CET

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$25$
B
$40$
C
$50$
D
$20$

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Alternating Current

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Only Inductor, Only Capacitor and Only Resistor Circuit

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An alternating voltage of $22 \, V$ is applied across an inductance coil of reactance $11 \, \Omega$. If the inductance of the coil is $0.07 \, H$, the frequency of the alternating voltage is: (in $ \, Hz$)

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